5(4-x)^2=7x(4-x)

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Solution for 5(4-x)^2=7x(4-x) equation: 



5(4-x)^2=7x(4-x)

We move all terms to the left:

5(4-x)^2-(7x(4-x))=0

We add all the numbers together, and all the variables

5(-1x+4)^2-(7x(-1x+4))=0



We calculate terms in parentheses: -(7x(-1x+4)), so:

7x(-1x+4)

We multiply parentheses

-7x^2+28x

Back to the equation:

-(-7x^2+28x)



We get rid of parentheses

7x^2-28x+5(-1x+4)^2=0

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